In a certain isosceles right triangle, the altitude to the hypotenuse has length 6. What is the area of the triangle?

Area(A) = [(sqrt2)6]² /2

A = 36u²

there doesnt have to be an explanation

The altitude in an isoceles right triangle creates two congruent triangles whose base and height are each = 6.

So .... 2 (1/2) b * h   =   2 (1/2) 36 = 36 sq units