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Ive got a formula, that i cant solve: N (t)= 17,5 * a^t, where t is years, and that is 30,17 years, but i need to find a, how do i do that

 Aug 30, 2014

Best Answer 

 #9
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+10

The question. A certain radioactive substance has a half-life of 30,17 years. in the model you can calculate the remaining substance, as a function of time: N (t) = 17.5*a^t, where N (t) is remaining substance (measured in grams) and "t" is time (measured in years)...

 

When t=0

N(0)=17.5*a^0 = 17.5  So the original amount of substance is 17.5 grams.

The half life is the amount of time it takes for the original to decrease by half so N(30.17)=17.5/2=8.75grams

$$8.75=17.5*a^{30.17}$$

Divide both sides by 17.5 and you get

$$0.5=a^{30.17}$$

Raise both sides to the power of (1/30.17) and you will have the value of a    

 Aug 30, 2014
 #1
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+5

$$N(30.17)=17.5*a^{30.17}$$

 

you have got 2 unknowns here. N(t) and a

You need to know what N(30.17 ) is before you can find a.

 Aug 30, 2014
 #2
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"N" is the amount of mass left after certain years, measured in grams

 Aug 30, 2014
 #3
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Yes I understand that but I need to know how much is left after 30.17 years in order to find a.

(or after any specific number of years for that matter)

It is not going to be the amount left either - the amount is growing all the time.

Perhaps you have an entire question that you can type in?

 Aug 30, 2014
 #4
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maybe i need to change the formular so it will say a=.. or something?

 Aug 30, 2014
 #5
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0

don't you have the original question in front of you?

Do you want to make a the subject?

 Aug 30, 2014
 #6
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The 30.17 years has no relevance unless you are given the N when t=30.17

 Aug 30, 2014
 #7
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The question. A certain radioactive substance has a half-life of 30,17 years. in the model you can calculate the remaining substance, as a function of time: N (t) = 17.5*a^t, where N (t) is remaining substance (measured in grams) and "t" is time (measured in years)...

 Aug 30, 2014
 #8
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0

Find "a" for the substance ??

 Aug 30, 2014
 #9
avatar+118608 
+10
Best Answer

The question. A certain radioactive substance has a half-life of 30,17 years. in the model you can calculate the remaining substance, as a function of time: N (t) = 17.5*a^t, where N (t) is remaining substance (measured in grams) and "t" is time (measured in years)...

 

When t=0

N(0)=17.5*a^0 = 17.5  So the original amount of substance is 17.5 grams.

The half life is the amount of time it takes for the original to decrease by half so N(30.17)=17.5/2=8.75grams

$$8.75=17.5*a^{30.17}$$

Divide both sides by 17.5 and you get

$$0.5=a^{30.17}$$

Raise both sides to the power of (1/30.17) and you will have the value of a    

Melody Aug 30, 2014
 #10
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0

Thank you soooo much Melody, can you please explain the last part, finding "a2 didnt get it :/

 Aug 30, 2014
 #11
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0

I'm lost, which bit didn't you understand?

 Aug 30, 2014

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