Just worked this question. It's rather fun. Can YOU do it?
log {3[1/3(10^x - 1)]} + 1
Nope ---
The 3 multiplied times the 1/3 = 1; so ignore them, leaving:
y = log(10^x - 1) + 1
As x gets larger, 10^x - 1 approaches 10^x, so log(10^x - 1) + 1 approaches log(10^x) + 1.
Since log(10^x) = x, y approaches x + 1.
