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Laverne starts counting out loud by 5's. She starts with 7. As Laverne counts, Shirley sums the numbers Laverne says. When the sum finally exceeds 5000, Shirley runs screaming from the room. What number did Laverne last say before Shirley flees?

 Jan 20, 2015

Best Answer 

 #2
avatar+128731 
+8

The sum of a series is given by

S = (n/2)[a1 + a1 + d(n - 1)]   where n is the number of terms, a1 is the first term,      a1 + d(n - 1) is the last term, and d is the common difference between terms .... so we have

S = (n/2)[ 7 +  7 + 5(n-1) ] > 5000

(n/2) [ 9 + 5n ]  > 5000

n[ 9 + 5n  ] > 10000

5n^2 + 9n - 10000 > 0   and solving this ...  n > 43 → n = 44

So...the last number said is

a44 = [ 7 +5(44 - 1) ] =  [ 7 +5(43) ]  = 222

 

 Jan 20, 2015
 #1
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+1

4997 because is like she started counting with 2

 Jan 20, 2015
 #2
avatar+128731 
+8
Best Answer

The sum of a series is given by

S = (n/2)[a1 + a1 + d(n - 1)]   where n is the number of terms, a1 is the first term,      a1 + d(n - 1) is the last term, and d is the common difference between terms .... so we have

S = (n/2)[ 7 +  7 + 5(n-1) ] > 5000

(n/2) [ 9 + 5n ]  > 5000

n[ 9 + 5n  ] > 10000

5n^2 + 9n - 10000 > 0   and solving this ...  n > 43 → n = 44

So...the last number said is

a44 = [ 7 +5(44 - 1) ] =  [ 7 +5(43) ]  = 222

 

CPhill Jan 20, 2015

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