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[m-50]*[m+18] =

 Sep 1, 2014

Best Answer 

 #2
avatar+128577 
+5

Nice BIG explanation, ND !!!   REALLY BIG !!!

I want to point out someting...."FOIL" is a useful method for expanding multiplied binomials. We could also do this....

(m - 50) (m + 18)

"Distribute" the "m" in the first set of parenthesis over the two terms in the other set of parenthesis...so we have......

m * m  + m *18   =  m2 + 18m

Them, do the same thing with the "-50"    ...and we have......

-50m - 900

And combining like terms, we have

m2 + 18m - 50 m - 900  =

m2 - 32m - 900   ......just as NinjaDevo found

The only reason I mention this is that "FOIL"  can't be effectively used if we are multiplying polynomials that involve more than two terms. In that case, another "ditribution" method is often necessary......!!!!

 

 Sep 1, 2014
 #1
avatar+3453 
+5

We need to multuply these two parentheses together. To do this, we need to use FOIL.

This means we have to multiply the First numbers, the Outside numbers, the Inside numbers, and the Last numbers. This spells FOIL! :)

 

So here's how you'd solve this:

And now you add these boxed number together.

 

 

The orange boxed number is the final answer.

 Sep 1, 2014
 #2
avatar+128577 
+5
Best Answer

Nice BIG explanation, ND !!!   REALLY BIG !!!

I want to point out someting...."FOIL" is a useful method for expanding multiplied binomials. We could also do this....

(m - 50) (m + 18)

"Distribute" the "m" in the first set of parenthesis over the two terms in the other set of parenthesis...so we have......

m * m  + m *18   =  m2 + 18m

Them, do the same thing with the "-50"    ...and we have......

-50m - 900

And combining like terms, we have

m2 + 18m - 50 m - 900  =

m2 - 32m - 900   ......just as NinjaDevo found

The only reason I mention this is that "FOIL"  can't be effectively used if we are multiplying polynomials that involve more than two terms. In that case, another "ditribution" method is often necessary......!!!!

 

CPhill Sep 1, 2014

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