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2а(а-1)+3(а-1)=

4х-4у+ах-ау=

2х^2-ху=

Guest Dec 23, 2015

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Best Answer

2а(а-1)+3(а-1) = (a - 1) (2a + 3)

4х-4у+ах-ау = 4(x - y) + a (x - y) = (4 + a) (x - y)

2х^2-ху = x (2x - y )

CPhill Dec 23, 2015

CPhill · Answer 1 · 2015-12-23T03:44:21

2а(а-1)+3(а-1) = (a - 1) (2a + 3)

4х-4у+ах-ау = 4(x - y) + a (x - y) = (4 + a) (x - y)

2х^2-ху = x (2x - y )