Ali, Bala, Clement and David shared some marbles. Ali took 28% of the marbles and Bala took 21% of the marbles. Clement took 1800 marbles more than Bala. David took the remaining 2700 marbles. How many marbles were there altogether?(help please, really hard question)
Let N be the number of total marbles
And we have that....
.28N + .21N + [.21N + 1800] + 2700 = N simplify
.7N + 4500 = N subtract .7N from both sides
4500 = .3N divide both sides by .3
4500 / .3 = N = 15,000
Yes, I can see it is a very conlfusing question. :)
Ali, Bala, Clement and David shared some marbles. Ali took 28% of the marbles and Bala took 21% of the marbles. Clement took 1800 marbles more than Bala. David took the remaining 2700 marbles. How many marbles were there altogether?(help please, really hard question)
Let Ali's share be A
Bala share is B
Clements share is C
David's share is D
Total is T and T=A+B+C+D
A=0.28T
B=0.21T
C=B+1800
D=2700
21/3*4=28 so 21* 4/3 = 28 B * 4/3 = A
so
A= 4/3 * B
B=B
C=B+1800
D=2700
T= A+B+C+D
\(T=A+B+C+D\\ T=\frac{4B}{3}+B+B+1800+2700\\ T=\frac{4B}{3}+2B+4500\\ T=\frac{4B+6B}{3}+4500\\ T=\frac{10B}{3}+4500\\~\\ but\\ B=0.21T\\ so\\ T=\frac{10*0.21T}{3}+4500\\ \frac{3T}{3}=\frac{2.1T}{3}+4500\\ \frac{0.9T}{3}=4500\\ 0.3T=4500\\ T=4500\div 0.3\\ T=15000 \)
There were 15000 marbles.
I have checked this answer and you should too :)
Hi Chris,
I did a good job of turning that mole hill into a little mountain didn't I LOL :D