Ali, Bala, Clement and David shared some marbles. Ali took 28% of the marbles and Bala took 21% of the marbles. Clement took 1800 marbles more than Bala. David took the remaining 2700 marbles. How many marbles were there altogether?(help please, really hard question)
Let N be the number of total marbles
And we have that....
.28N + .21N + [.21N + 1800] + 2700 = N simplify
.7N + 4500 = N subtract .7N from both sides
4500 = .3N divide both sides by .3
4500 / .3 = N = 15,000
Yes, I can see it is a very conlfusing question. :)
Ali, Bala, Clement and David shared some marbles. Ali took 28% of the marbles and Bala took 21% of the marbles. Clement took 1800 marbles more than Bala. David took the remaining 2700 marbles. How many marbles were there altogether?(help please, really hard question)
Let Ali's share be A
Bala share is B
Clements share is C
David's share is D
Total is T and T=A+B+C+D
A=0.28T
B=0.21T
C=B+1800
D=2700
21/3*4=28 so 21* 4/3 = 28 B * 4/3 = A
so
A= 4/3 * B
B=B
C=B+1800
D=2700
T= A+B+C+D
T=A+B+C+DT=4B3+B+B+1800+2700T=4B3+2B+4500T=4B+6B3+4500T=10B3+4500 butB=0.21TsoT=10∗0.21T3+45003T3=2.1T3+45000.9T3=45000.3T=4500T=4500÷0.3T=15000
There were 15000 marbles.
I have checked this answer and you should too :)
Hi Chris,
I did a good job of turning that mole hill into a little mountain didn't I LOL :D