+55 vehicle a departs at 64km/h. 2 1/4 hours later, vehicle b follows at 112km/h. how long will it take b to catch up to a?
+118609 vehicle a departs at 64km/h. 2 1/4 hours later, vehicle b follows at 112km/h. how long will it take b to catch up to a?
The first vehicle has a 2.25*64 = 144km head start.
So now I will take the time from where the second vehicle leaves.
At any point in future time let t be in hours
Vehicle 1 will have travelled 144+ 64t
Vehicle 2 will have travelled 112t
They will be at the same point when,
144+64t=112t
144 = 48t
t = 144/48 = 3 hours
vehicle a departs at 64km/h. 2 1/4 hours later, vehicle b follows at 112km/h. how long will it take b to catch up to a?
Let the time taken by "a"= t
64t = 112(t - 2.25), solve for t
t = 21/4 =5 1/4 hours - time taken by "a"
5.25 - 2.25 = 3 hours - when "b" will catch up with "a"
