+25 Bob builds a rectangular room inside a building of side length 3(x+2) and width (x-2). He decides to put a rubber surface on the floor of the room. The lengths of the room run parallel. Write an algebraic fraction in simplest form for the fraction of the area of the floor of the shed covered in rubber surface. Show all working out.
Thank you heaps!!
+118652 Bob builds a rectangular room inside a building of side length 3(x+2) and width (x-2). He decides to put a rubber surface on the floor of the room. The lengths of the room run parallel. Write an algebraic fraction in simplest form for the fraction of the area of the floor of the shed covered in rubber surface. Show all working out.
I reallydo not understand this quesiton but if the room is length 3(x+2) and width (x-2)
then the area is 3(x+2) multiplied by (x-2) units squared
Area = 3(x+2)(x-2) units squared
+118652 Bob builds a rectangular room inside a building of side length 3(x+2) and width (x-2). He decides to put a rubber surface on the floor of the room. The lengths of the room run parallel. Write an algebraic fraction in simplest form for the fraction of the area of the floor of the shed covered in rubber surface. Show all working out.
I reallydo not understand this quesiton but if the room is length 3(x+2) and width (x-2)
then the area is 3(x+2) multiplied by (x-2) units squared
Area = 3(x+2)(x-2) units squared
