Hello can you help me about what is the formula for 1^1+2^2+3^3...
1^2 + 2^2 + 3^2 + ..... + n^2 = [ n * ( n + 1) * (2n + 1) ] / 6
Sorry but it wasn't the response i wanted it's 1^1+2^2+3^3+4^4+5^5+6^6... not 1^2 + 2^2 + 3^2, it's almost like a hyperfactorial but it use 1^1 * 2^2 * 3^3... instead of 1^1+2^2+3^3.
I don't think you will find a shortcut, because the growth is exponential, and thereby unpredictable. I could be wrong!.
