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Suppose that a one-to-one function f has tangent line y = 5x+ 3 at the point (1, 8). Evaluate (f^{-1})'(8)

 Oct 16, 2015

Best Answer 

 #3
avatar+33654 
+5

I thought this was interesting too.  I'd like to make it both simpler (1. below) and more complicated (2. below)!

 

inverse functions

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 Oct 18, 2015
 #1
avatar+6251 
+5

what do you know about the relationship between f(x) and (f1)(x)?

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 Oct 16, 2015
 #2
avatar+118696 
+5

Rom, I hope that you do not mind me butting in but i could not answer your questions straight off and I wanted to think about what was happening myself.

 

So whether or not you are teaching the question asker, you are teaching me:)

 

I developed a formula for a curve that met the given criterion.

 

This is what I came up with.  

 

https://www.desmos.com/calculator/7uhpqmscci

 

 

I/You did not need to do any of this to answer the question, I was just thinking laterally. :)

 

The answer is very simple.

 Oct 17, 2015
edited by Melody  Oct 17, 2015
 #3
avatar+33654 
+5
Best Answer

I thought this was interesting too.  I'd like to make it both simpler (1. below) and more complicated (2. below)!

 

inverse functions

.

Alan Oct 18, 2015
 #4
avatar+118696 
0

Thanks Alan,

 

 

In response to 1).

 

Yes of course I could have   frown      LOL

BUT

The graph would not hve looked as interesting   laugh

 

 

 

In response to 2)

That makes my head hurt.    angry

Maybe I will think about it later after something deadens the pain.      angrycryingangry       LOL   again    wink

 Oct 18, 2015
 #5
avatar+33654 
+5

1. You are right Melody, the graph would have been really boring!  

 

2. Here are a couple of graphs to illustrate the solution when n = 2 (so f(x) = x5 + 7) 

 

n=2

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 Oct 18, 2015
 #6
avatar+118696 
0

Thanks Alan,  I still like my graph.          laughwinklaugh   

 

I need to look at your number 2 answer properly :))

 Oct 18, 2015
edited by Melody  Oct 18, 2015
 #7
avatar+6251 
0

all very nice work but you all seemed to have missed the point

 

(f1)(x)=1f(f1(x))

 

So as f has a tangent line y=5x+3,@(1,8)f1(8)=1f(1)=15(1)+3=18

 Oct 20, 2015

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