+0

# Momentum

+5
750
4

A man standing on very slick ice fires a rifle horizontally. The mass of the man together with the rifle is 70 kg , and the mass of the bullet is 10 g . If the bullet leaves the muzzle at a speed of 500 m/s , what is the final speed of the man?

Guest Feb 17, 2016

### Best Answer

#3
+1311
+5

This is called conservation of momentum

Mass * velocity  =   momentum

Solve it like this

m1 * v1 = m2 * v2

0.010kg x 500m/s = 70kg * v2

(0.010*500)/70 =0.0714

The final speed of the man is 0.0714 m/s

Dragonlance  Feb 17, 2016
Sort:

### 4+0 Answers

#1
0

Zero b***h

Guest Feb 17, 2016
#2
+333
0

we must first figure out the force of the bullet with

F=ma so 10g*500  =5000N

So the bullet will produce a horizontal force of 5000N

so 5000N at the speed of 500/ms

the final speed is 5000/500=10/ms(^-2) in horizontal force

Sorry if i made some mistakes, i'm not amazing at physics

Misaki  Feb 17, 2016
#3
+1311
+5
Best Answer

This is called conservation of momentum

Mass * velocity  =   momentum

Solve it like this

m1 * v1 = m2 * v2

0.010kg x 500m/s = 70kg * v2

(0.010*500)/70 =0.0714

The final speed of the man is 0.0714 m/s

Dragonlance  Feb 17, 2016
#4
+91001
0

Physics is neat!  Thanks Dragonlance.

Melody  Feb 17, 2016

### 8 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details