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 Given a function f(x) and a point x=a, the linear function

T_1(x) = f(a) + f'(a)(x-a)

is called the first-order Taylor polynomial of f(x) about x=a.  (Note that this is an equation for the tangent line to the graph of f at the point x=a.)  Determine T_1(x) for the function f(x) = e^{18.4x} about the point  x=11.2 .

 

T_1(x)=

 Nov 23, 2014

Best Answer 

 #1
avatar+23246 
+5

The derivative of  e^(18.4x)  =  e^(18.4x) · 18.4  =  18.4e^(18.4x)

f(11.2)  =  e^(18.4 · 11.2)  =  e^(206.08)

f'(11.2)  =  18.4e^(18.4 · 11.2)  =  18.4e^(206.08)

T1(x)  =  e^(206.08) + 18.4e^(206.08) · (x - 11.2)

Use can use a calculator to get a decimal approximation for f(11.2) and f'(11.2). 

 Nov 23, 2014
 #1
avatar+23246 
+5
Best Answer

The derivative of  e^(18.4x)  =  e^(18.4x) · 18.4  =  18.4e^(18.4x)

f(11.2)  =  e^(18.4 · 11.2)  =  e^(206.08)

f'(11.2)  =  18.4e^(18.4 · 11.2)  =  18.4e^(206.08)

T1(x)  =  e^(206.08) + 18.4e^(206.08) · (x - 11.2)

Use can use a calculator to get a decimal approximation for f(11.2) and f'(11.2). 

geno3141 Nov 23, 2014

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