How would i find this on the unit circle? or am i suppose to use the calculator? I only have one try to enter the correct answer and im not sure how they want it. Cause i could try to find the angles, or i could just enter it in the calculator and then do the inverse of the that answer.
14pi/ 19 > pi/2 ......so......we need to convertt this angle to fall within the range of the arcsin which is between -pi/2 and pi/2
Note....... sin A = sin (pi - A) ....so....
sin [ pi - 14pi/19 ] = sin [ (19pi - 14pi) /19 ] = sin (5pi/19)
arcsin (sin (5pi / 19) ) = 5pi / 19
[ Remember, for example... arcsin ( sin pi/6) = arcsin (1/2) = pi/6 ]