+118703 Hi Zac,
Thanks for answering these questions :)
There is a couple of things here.
1) I think it should be 10t2+5t−2=0(NOT−5t)
2) I am not sure what the asker INTENDED the question to be BUT this was the question.
1/2+2/5t-1=1/5t+t
Technically this should be interpreted as
12+25t−1=15t+t12+2t5−1=1t5+t$Thetisonthetop$−12+2t5=6t5−12=4t5−1∗52∗4=tt=−58
Also, I would like you to consider putting in some blank lines.
Sometimes mine is spread out too much, I realize that, but I personally find it a bit hard to read when there are no spaces. This may just be a peronal preference. I am not sure :/
+980 I'm not sure if it's right, but I ended up with a quadratic by the end. Here goes:
12+2(5×t)−1=1(5×t)+t Take the 1/5t off both sides.
12+1(5×t)−1=t Multiply everything by 10t.
(10×t)2+(10×t)(5×t)−10×t=10×t2 Simplify.
5×t+2−10×t=10×t2
10×t2−5×t−2=0 Now using the quadratic formula,
t=−b+√b2−4ac2a or t=−b−√b2−4ac2a
a=10, b=-5, c=-2
t=5+√52−4×10×−22×10 or t=5+√52−4×10×−22×10
t=5+√25+8020 or t=5−√25+8020
t=5+√10520 or t=5−√10520
which works out to ≈ 0.76235 or -0.26235.
P.S. I don't know how to say "plus minus" something.
+118703 Hi Zac,
Thanks for answering these questions :)
There is a couple of things here.
1) I think it should be 10t2+5t−2=0(NOT−5t)
2) I am not sure what the asker INTENDED the question to be BUT this was the question.
1/2+2/5t-1=1/5t+t
Technically this should be interpreted as
12+25t−1=15t+t12+2t5−1=1t5+t$Thetisonthetop$−12+2t5=6t5−12=4t5−1∗52∗4=tt=−58
Also, I would like you to consider putting in some blank lines.
Sometimes mine is spread out too much, I realize that, but I personally find it a bit hard to read when there are no spaces. This may just be a peronal preference. I am not sure :/
