I just saw your reply and i am still having a bit of trouble understanding the concept... I have another example if you could further explain.
A family goes to a school play. Two adult tickets and 1 student ticket cost $8.75. Another family needs 1 adult ticket and 4 student tickets. Their total cost was $10.50. Find the price of each type of ticket.
Huge thanks in advance!!
+33616 Represent the cost of an adult ticket by 'at' and the cost of a student ticket by'st'.
For the first family 2*at + 1*st = 8.75
For the 2nd family 1*at + 4*st = 10.50
From the 2nd family's equation, if we subtract 4*st from both sides we have 1*at = 10.50 - 4*st, which tells us the cost of an adult ticket in terms of the cost of student tickets. The first family paid for 2 adult tickets which means they must have paid the equivalent of 2*(10.50 - 4*st) or 21 - 8*st for their 2 adult tickets. Replacing the 2*at in their equation we get, for the first family, that:
21 - 8*st + 1*st = 8.75
or 21 - 7*st = 8.75
Add 7*st to both sides and subtract 8.75 from both sides;
21 - 8.75 = 7*st
12.25 = 7*st
Divide both sides by 7 to find
st = 12.25/7 = 1.75
So the price of a student ticket is $1.75
Put this back in the equation for the 2nd family and we get
1*at + 4*1.75 = 10.50
at + 7 = 10.50
Subtract 7 from both sides
at = 10.50 - 7 = 3.50
so the price of an adult ticket is $3.50
+11912 Anonymous , if you couldnt understand the answer properly then instead of making a new post it would be better if you could ask the person who answered your question to explain it a lil more further in the same thread like all others!But im just advising ,you can follow whatever u feel is good!
Correction:sorry i didnt read your question properly and gave u my advice!
actually as this question is much similar to your last one so i just got distracted!sorry !
+11912 Its okay!And isnt it funny , we both have made mistakes at the same time and are apologizing!
And im too sorry for not reading your post correctly !i just thought u posted the same question again and didnt notice it was a new one!
Nevermind, im happy you'd follow my advice next time!
I find it funny aswell! On another note, can we maybe focus on the problem at hand? *points at above math problem.*
+33616 Represent the cost of an adult ticket by 'at' and the cost of a student ticket by'st'.
For the first family 2*at + 1*st = 8.75
For the 2nd family 1*at + 4*st = 10.50
From the 2nd family's equation, if we subtract 4*st from both sides we have 1*at = 10.50 - 4*st, which tells us the cost of an adult ticket in terms of the cost of student tickets. The first family paid for 2 adult tickets which means they must have paid the equivalent of 2*(10.50 - 4*st) or 21 - 8*st for their 2 adult tickets. Replacing the 2*at in their equation we get, for the first family, that:
21 - 8*st + 1*st = 8.75
or 21 - 7*st = 8.75
Add 7*st to both sides and subtract 8.75 from both sides;
21 - 8.75 = 7*st
12.25 = 7*st
Divide both sides by 7 to find
st = 12.25/7 = 1.75
So the price of a student ticket is $1.75
Put this back in the equation for the 2nd family and we get
1*at + 4*1.75 = 10.50
at + 7 = 10.50
Subtract 7 from both sides
at = 10.50 - 7 = 3.50
so the price of an adult ticket is $3.50
