+118609
There are 24 Persons (p1,p2,p3,......) from which a team of 12 Persons has to be made. p1 and p2 can only come together in the team. p3 and p4 can never come together in the team. In how many ways can the team be formed?
If there were no restrictions at all then there would be 24C12 = 2,704,156 ways.
It has to be a lot less then that
This is what I am thinking.
Say we take those 4 out and deal with them seperately. Then we will only be chosing from 20 people
P1 and P2 are chosen, P3 is chosen and P4 is NOT chosen 3 in aready 20C9
P1 and P2 are chosen, P3 is NOT chosen and P4 is chosen 3 in aready 20C9
P1 and P2 are chosen, P3 is NOT chosen and P4 is NOT chosen 2 in already 20C10
P1 and P2 are NOT chosen, P3 is chosen and P4 is NOT chosen 1 in already 20C11 = 20C9
P1 and P2 are NOT chosen, P3 is NOT chosen and P4 is chosen 1 in already 20C11 = 20C9
P1 and P2 are NOT chosen, P3 is NOT chosen and P4 is NOT chosen 0 in already 20C12
20C9+20C9+10C10+10C9+20C9+20C12 = 4 * 20C9 + 20C10 + 20C12
These are the possibilities4*nCr(20,9)+nCr(20,10)+nCr(20,12) = 982566
So I think that there are 982,566 possible choices. ://
