+244 On the Moon, the acceleration of gravity is one sixth of it's value here on earth. If a pendulum has a period of T on here on earth Earth, what will its period be on the Moon?
A.T/
B.T
C.T/6
D.T/3
E.6T
You question doesn't make sense to me for the answers given. Because the period of a pendulum should vary as the square root of the gravity ratio between the Earth and the Moon. That is, if the gravity on Earth is 6 times that on the Moon, then the period on the Moon should be:
Tsqrt(6) =2.46T. But, I don't see that on your list of choices!!. Sorry, unless I'm neglecting something.
Alan should take a look at it.
+14919 Hi Damien!
On the Moon, the acceleration of gravity is one sixth of it's value here on earth. If a pendulum has a period of T on here on earth Earth, what will its period be on the Moon?
A.T/
B.T
C.T/6
D.T/3
E.6T
\(T= 2\pi \times \sqrt{\frac{l}{g} }\)
\(T_{M} = 2\pi \times \sqrt{\frac{6\times l}{g} }\)
TM = T \(\times \sqrt{6} \) = 2.45 T
A. T = TM / \(\sqrt{6}\)
The time for one oscillation of the pendulum on the moon is 2.45 times the time of a vibration on the earth.
Greeting asinus :- )
!
