+259 I hope this is the right topic for a math forum.
The topic doesnt seem difficult but just that one thing really nagged on me.
When having a conductor in a magnetic field with electrons having the speed\({V}_{d}\) the magnetic field having the magnetic flux density B and thus the Lorentz force from b to a with a strength of \({F}_{L}\)the electrons will drive to the bottom(example).
This will make the conductor have a surplus of electrons on the bottom and thus a shortage of electrons on the top.
Now my question is what if you have a p-type semiconductor? In a p-type semiconductor you have those "holes" that are said to be positiv and that go the opposite direction as electrons(from + to - in the conductor). But since u still have electrons who will go through the conductor, the Lorentz force will let the electrons create a surplus of electrons on the bottom. Now since the electrons create a surplus on the bottom a, there must be a positive charge on the top b, which means those holes must be on the top?
Well thats whats confuses me, because if this is true, how can the conductor still conduct the electrons?
I mean the electrons need to hop from hole to hole to conduct the electricy, but since u got the Lorentz force dragging the Electrons down to the bottom, and the holes being on the top how does the conductor still conducts electricity.
Well the other part that kinda confuses me, is that there is the right hand 3 finger rule for positive charged particles.
When using the thumb for \({V}_{d}\)going from right to left, having B unchanged, \({F}_{L}\)goes into the same direction as the electrons. So the holes are supposed to create a surplus of positiv charge on the bottom a, and the electrons are supposed to create a surplus of negative charge on the bottom a. Does those both charges eliminate each other?
I hope this is understandable, if there are any questions to my question i will gladfully try to explain what i dont understand.
+36916 When you have a WIRE conductor moving in a magnetic field the electrons gather at on end creating a net NEGATIVE charge at that end and a net POSITIVE charge at the other end. No CURRENT will flow unless a circuit load is connected to the ends outside of the field ....this is how our electricity is generated and then used. With a p-type semiconductor, the process isn't really different....the POSITIVE charges will gather at one side and there will be a equal NEGATIVE charge at the other side . If you connect a conductor load to the sides, an electron will leave the NEGATIVE end....this creates a 'hole' which will migrate to the other side......at the SAME time this eletron leaves via the condutor another electron ENTERS on the POSITIVE hole side.....this 'fills a hole' so to speak...and this electron will then migrate through the substrate to the negative side to be with his electron buddies filling holes and jumping all of the way. Not all of the holes and electrons will gather at the sides...thee is always some available throughout the substrate to do this.
This might help with your RHR question:
http://physicsed.buffalostate.edu/SeatExpts/resource/rhr/rhr.htm
