+564 A 3.25-kg block of silver is dropped from rest at a height of 75.0 meters. One third of the potential energy is converted into heat energy which raises the temperature of the silver. The specific heat of silver is 234 joules per kilogram per Celsius degree. What is the increase in temperature of silver?
Been having a bit of trouble with this one :/
+33616 The potential energy is given by mass*g*height where g is the acceleration of gravity (9.81m/s^2), so energy used to heat silver is (1/3)*3.25*9.81*75 Joules
This energy equals mass*specific heat*temperature rise in the silver, so (1/3)*3.25*9.81*75 = 3.25*234*TempRise which gives a temperature rise of
$${\frac{\left({\frac{{\mathtt{1}}}{{\mathtt{3}}}}\right){\mathtt{\,\times\,}}{\mathtt{9.81}}{\mathtt{\,\times\,}}{\mathtt{75}}}{{\mathtt{234}}}} = {\mathtt{1.048\: \!076\: \!923\: \!076\: \!923\: \!1}}$$ degrees C
+33616 The potential energy is given by mass*g*height where g is the acceleration of gravity (9.81m/s^2), so energy used to heat silver is (1/3)*3.25*9.81*75 Joules
This energy equals mass*specific heat*temperature rise in the silver, so (1/3)*3.25*9.81*75 = 3.25*234*TempRise which gives a temperature rise of
$${\frac{\left({\frac{{\mathtt{1}}}{{\mathtt{3}}}}\right){\mathtt{\,\times\,}}{\mathtt{9.81}}{\mathtt{\,\times\,}}{\mathtt{75}}}{{\mathtt{234}}}} = {\mathtt{1.048\: \!076\: \!923\: \!076\: \!923\: \!1}}$$ degrees C
