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# Please and thank you! <3 ^.-

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Graph the function: Y=x^2+4x+3..

Vertex:

Axis of Symmetry:

Domain:

Range:

ANY HELP IS MUCH APRECIATED!! (;

Hayley1  Dec 14, 2015

#11
+91039
+5

Graph the function: Y=x^2+4x+3..

Vertex:

Axis of Symmetry:

Domain:

Range:

$$y=x^2+4x+3$$

This is a parabola because it is a polynomial of degree 2  (The highest power of x is 2)

There is an invisable +1 in front of the x^2    (1 is the leading coefficient)

Since the leading coefficient is positive the parabola is concave up.

$$y=x^2+4x+3\\ y=(x+3)(x+1)\\$$

The roots of the parabola are where y=0

y will equal zero when  x+3=0  and when  x+1=0

roots are x = -3  and x = -1

The axis of symmetry will be half way between the roots

x=(-3+-1)/2 = -4/2 = -2

Axis of symmetry is   x = -2

When x=-2    y=2^2-4*2+3 = 4 -8 +3 = -1   So the vertex is (-2, -1)

Domain:  $$x \in Z$$  (x can be anything)

Range:      $$y\ge-1$$

The vertex is where y=-1 so this is the lowest value that y can take.

and here is the graph

https://www.desmos.com/calculator/jypgvfhfex

Hopefully you can get a lot from this Hayley but if you have questions, make sure you ask :D

Melody  Dec 14, 2015
Sort:

#1
0

I guess your question is so difficult no one wants to answer it?

Guest Dec 14, 2015
#2
+8621
0

I guess :(

But Melody is an amazing person and is trying to help me!!

( I hope..)

Hayley1  Dec 14, 2015
#3
+2

Melody is awesome! I'll pray she helps ya lol.๐

Guest Dec 14, 2015
#4
+8621
0

Thanks!

The struggle is real right now!

Hayley1  Dec 14, 2015
#5
0

Huh. Make a post saying that you are losin faith in Melody. That would be funny๐

Guest Dec 14, 2015
#6
+8621
0

Noo! she would k**l me!!

She wouldn't like me anymore!

Hayley1  Dec 14, 2015
#7
0

Hahaha! I can do it for you.

Guest Dec 14, 2015
#8
+8621
0

haha. They work there bottoms off to help us!!!!

I greatly appreciate it Melody & Alan.

Thank you a lot!!

Like i said..

Anything is helpful information!

Hayley1  Dec 14, 2015
#9
+26329
+5

This should help:

Domain is from -infinity to infinity.  The range is all the valid values of y.  The graph should help you to figure that out.

Alan  Dec 14, 2015
#10
+8621
0

Thank you!

But, unfortunaly..

i cannot see it :(

Hayley1  Dec 14, 2015
#11
+91039
+5

Graph the function: Y=x^2+4x+3..

Vertex:

Axis of Symmetry:

Domain:

Range:

$$y=x^2+4x+3$$

This is a parabola because it is a polynomial of degree 2  (The highest power of x is 2)

There is an invisable +1 in front of the x^2    (1 is the leading coefficient)

Since the leading coefficient is positive the parabola is concave up.

$$y=x^2+4x+3\\ y=(x+3)(x+1)\\$$

The roots of the parabola are where y=0

y will equal zero when  x+3=0  and when  x+1=0

roots are x = -3  and x = -1

The axis of symmetry will be half way between the roots

x=(-3+-1)/2 = -4/2 = -2

Axis of symmetry is   x = -2

When x=-2    y=2^2-4*2+3 = 4 -8 +3 = -1   So the vertex is (-2, -1)

Domain:  $$x \in Z$$  (x can be anything)

Range:      $$y\ge-1$$

The vertex is where y=-1 so this is the lowest value that y can take.

and here is the graph

https://www.desmos.com/calculator/jypgvfhfex

Hopefully you can get a lot from this Hayley but if you have questions, make sure you ask :D

Melody  Dec 14, 2015
#12
+8621
0

Thank you so much!!

You're so so helpful!!

<3333333

Thaank you, Alan!!

You're very helpful, too!

<3333

Hayley1  Dec 14, 2015
#13
0

Not my question but I was getting tired waiting for the answer to that one.

Guest Dec 14, 2015
#14
+91039
0

Thank you Hayley and guest for your glowing refernces BUT how am i going to fit my head through any door now????

Hi Alan :))

Melody  Dec 14, 2015
#15
+8621
0

whatttt...?

:D

Hayley1  Dec 14, 2015
#16
0

I just needed to add my 2 cents. Although it ain't worth much๐

Guest Dec 14, 2015
#17
0

I'll be happy to do it any time...

Guest Dec 14, 2015
#18
+91039
0

All the praise has gone to my head and now it is very swollen so I do not know if it will fit through doorways anymore.  ://

Melody  Dec 14, 2015
#19
0

Good one๐๐๐ผ

Guest Dec 14, 2015
#20
+8621
0

LOOOL!!

Hayley1  Dec 14, 2015
#21
0

Also Haley1 ya kinda ruin good ( puns etc.) when ya ask for an explanation.

Guest Dec 14, 2015
#22
+91039
0

Thanks guest,

You are welcome to put your 2 cents in :))

Melody  Dec 14, 2015
#23
+8621
0

Leave me alone!

haha :)

Hayley1  Dec 14, 2015
#24
+91039
0

NO Hayley didn't ruin it.

She should always ask when she does not understand :)

Melody  Dec 14, 2015
#25
+8621
0

Exxactlyy!!!!

Haa!

She's on my side!!

Hayley1  Dec 14, 2015
#26
0

It was the purpose of my creation to annoy people... And I pride myself on being good at it. In fact I have only been slugged 4 times. But they got hurt back so my " attackers" and I are even.

Guest Dec 14, 2015
#27
0

Yeah I know she didn't ruin it in this case but I hate it when I have a good comment and then someone asks me to repeat it or something... It just doesn't seem as good the second time around.

Guest Dec 14, 2015
#28
+8621
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I have a huge project i have to do.. :/

It's on drivers ed!

Hayley1  Dec 14, 2015
#29
+8621
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Can i put pictures on here that i screen shot form my laptop??

Hayley1  Dec 14, 2015
#30
0

I should make that my motto " Ask in yo will totally understand" it's sounds a little better than ask and yo shall receive. Don't ya think.

Guest Dec 14, 2015
#31
0

What is drivers ed

Guest Dec 14, 2015
#32
0

I dunno bout pics.

Can Yo?

Guest Dec 14, 2015
#33
+8621
0

uggggghhh.. :/

Hayley1  Dec 14, 2015
#34
0

I take it ughhhhhh was response to 3ed post what bout second one.

Guest Dec 14, 2015
#35
+8621
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i dont no how to post pictures that i screen shot :/

Hayley1  Dec 14, 2015
#36
0

Neither do I bro!

Guest Dec 14, 2015
#37
+8621
0

pftt Broo.

Your a girl, Right?

Hayley1  Dec 14, 2015
#38
0

My #31 question is getting bored.

Guest Dec 14, 2015
#39
+8621
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haha, drivers ed is a class where i can learn to drive better, so that i dont drive crazy ^-^

Hayley1  Dec 14, 2015
#40
0

Noooooo. Why the h**l would yo accuse me of being a girl.

Guest Dec 14, 2015
#41
+8621
0

hehe. Sowwiee!

Hayley1  Dec 14, 2015
#42
0

JJ I am a girl but I am a tomboy.  My name is Victoria but don't use my name cause I hate it.

Guest Dec 14, 2015
#43
0

I've talked to yo before and told yo ma name... I think or that could have been Katie Leigh I told ma name to.

Guest Dec 14, 2015
#47
0

Sup? No one answering ma posts dude that's mean.

Guest Dec 14, 2015
#48
+8621
0

im here!

Working on some projectss

Hayley1  Dec 14, 2015
#49
0

Cool way projects? Once I made a guillotine but I made it smash a watermelon it was messy but awesome.

Guest Dec 14, 2015
#50
+8621
0

LOL! driving project, science project.. Finals study guides

Hayley1  Dec 14, 2015
#51
0

Oh... Less awesome. Is yo profile pic of yo I wish I had blonde hair but it would be kinda useless cuz I died ma hair orange and black.

Guest Dec 14, 2015
#53
+8621
0

hehehehe

Hayley1  Dec 14, 2015
#55
+91039
0

Driver's Ed would stand for Driver's Education.

Hayley can tell you more about what it is :/

Melody  Dec 14, 2015
#56
+8621
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Yupp :)

Its a great class!

Hayley1  Dec 14, 2015
#57
0

I'm gonna be 25 fore I can drive a car. I always press gas to hard and the vehicle like goes on two. It is fun though also I e only driven a golf cart and four wheeler. Once I pressed the gas to hard and ma friend fell off she was out for carnage after that.

Guest Dec 14, 2015
#58
+8621
0

is that you victoria?

I cannot tell..

So many guests

Hayley1  Dec 14, 2015
#59
0

Yeah it's me but I did tell ya not to call me Victoria.

Guest Dec 14, 2015
#60
+8621
0

oh, sorry

Hayley1  Dec 14, 2015
#61
0

Sok, I gotta go now am mom is probabaly gonna be waking up soon. Peeps who go to school dunno how easy they got it.

Guest Dec 14, 2015
#62
+8621
0

LOOL.

Goodbye. (:

Hayley1  Dec 14, 2015

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