Let a,b,c be vectors such that a×b=(−1−1−1),a×c=(−121), and b×c=(023) Then evaluate (b+c)×b,a×(b+4a),(a+b+c)×a
For cross products we have the following
a x a = 0 (simiarly for b x b etc)
a x b = - b x a etc.
(b + c) x a = b x a + c x a = -a x b - a x c etc.
Can you take it from here?
Thanks Alan, that sure made it easy