please help!!!!!!!!

Solve for x:

1/4 + 1/6 - 1/x =1/12 , solve for x
5/12-1/x = 1/12

Bring 5/12-1/x together using the common denominator 12 x:
(5 x-12)/(12 x) = 1/12

Cross multiply:
12 (5 x-12) = 12 x

Expand out terms of the left hand side:
60 x-144 = 12 x

Subtract 12 x-144 from both sides:
48 x = 144

Divide both sides by 48:
Answer: |  x = 3  OR THE FRACTION IS: 1/3

Here's the way I see this one.......

Let x be the fraction......and we have

 [(1/4) + (1/6) - x ] / 3  =  1/12    simplify

[ 10/24 - x] / 3  =  = 1/12   multiply both sides by 3

10/24 - x =  3/12      simplify

5/12  - x =  1/4         rearrange

5/12 - 1/4  = x      simplify again

5/12  -  3/12   = x

2/12  = x    

1/6 = x

We seem to need an adjudicator here   :))

What fraction must be subtracted from sum of 1/4 and 1/6 to have an avg of 1/12 of all the three fractions?

\(\frac{[\frac{1}{4}-x]+[\frac{1}{6}-x]+x}{3}=\frac{1}{12}\\ [\frac{1}{4}-x]+[\frac{1}{6}-x]+x=\frac{3}{12}\\ \frac{1}{4}-x+\frac{1}{6}-x+x=\frac{1}{4}\\ \frac{1}{4}+\frac{1}{6}-x=\frac{1}{4}\\ \frac{1}{6}-x=0\\ x=\frac{1}{6}\\ \)

Yep - I got to agree with CPhill on this one :))