Find three consecutive integers such that twice the sum of the first two is less than three times the third.
n, n+1, n+2
2[n+n+1] < 3[n+2], solve for n
n < 4 . This could apply to:
1, 2, 3 OR 2, 3, 4 OR 3, 4, 5
at 4, 5, 6 both sides will be equal. You made this one up yourself, didn't you?
