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Point C is on AC such that AX=3CX. If ABC=BXA=90°, then what is BX?

Mellie  Nov 12, 2015

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 #1
avatar+78574 
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[ I think this is supposed to read..."Point X  is on AC such that......." ]

 

 Triangle AXB ≈ Triangle BXC

 

 AX/XB ≈ BX/XC

 

AX*XC  = XB*BX

 

AX*CX  = BX^2

 

(3CX)CX  = BX^2

 

3CX^2  = BX^2

 

sqrt(3)CX  = BX

 

Here's the pic :

 

 

 

 

cool cool cool

CPhill  Nov 13, 2015
edited by CPhill  Nov 13, 2015
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1+0 Answers

 #1
avatar+78574 
+10
Best Answer

[ I think this is supposed to read..."Point X  is on AC such that......." ]

 

 Triangle AXB ≈ Triangle BXC

 

 AX/XB ≈ BX/XC

 

AX*XC  = XB*BX

 

AX*CX  = BX^2

 

(3CX)CX  = BX^2

 

3CX^2  = BX^2

 

sqrt(3)CX  = BX

 

Here's the pic :

 

 

 

 

cool cool cool

CPhill  Nov 13, 2015
edited by CPhill  Nov 13, 2015

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