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What's the formula for solving equations like 5^n = 3125

 Jul 21, 2016

Best Answer 

 #1
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+5

Take logs of both sides.Always the same technique. 

 

If 5^n =3125

then log(5^n) = log 3125

n log 5 = log 3125

n= (log 3125)/log5. 

log 3125 = 3.495 approx  and     log 5 = 0.7 approx

so answer in this case is

n=3.495/0.7 = 4.99 approx. ( I  rounded off the numbers,you will see that if you

raise 5 to the power 4.99 you actually get 3075)

 Jul 21, 2016
 #1
avatar
+5
Best Answer

Take logs of both sides.Always the same technique. 

 

If 5^n =3125

then log(5^n) = log 3125

n log 5 = log 3125

n= (log 3125)/log5. 

log 3125 = 3.495 approx  and     log 5 = 0.7 approx

so answer in this case is

n=3.495/0.7 = 4.99 approx. ( I  rounded off the numbers,you will see that if you

raise 5 to the power 4.99 you actually get 3075)

Guest Jul 21, 2016
 #2
avatar+36916 
+5

Agree with Guest #1  ... if you do it all on the calculator without 'rounding' you will find n = 5

 Jul 21, 2016

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