+69 How would the graphs of
a)
x=t
y=2t+1
b)
x=e^t
y=2e^t +1
c)
x=cos(t)
y=2cos(t)+1
>>>> Image of Question: http://i.imgur.com/rPPo9Dy.jpg <<<<
Sorry about all the questions im just stuck on some questions on this test review and this is by far one of the most helpful sites.
+128731 Every one of these can be transformed into the linear equation y= 2x + 1.....the behavior [ and definition] of the last two differs slightly from the first "parent" graph
Here's a graph of the first one...it's the same graph as y = 2x + 1
Here's a graph of the second :
Notice that it's very similar to the first, except that it is not defined for any x less than or equal to 0 because an exponential can never be 0 or negative......thus, we might say that this graph is the first quadrant representation of the first one where x > 0
Here's the last one :
Note that this one is a "truncated" graph of the first....at t =0, we have the point (1,3).....then, as t increases from 0 to pi/2, the motion is back towards the y axis [an x axis, as well] until we get to the point (0, 1).....as t increases from pi/2 to pi......the motion proceeds to (-1, -1).....from pi to 3pi/2 the motion now proceeds back to (0,1).....and as t increases from 3pi/2 to 2pi, the motion proceeds back to the starting point of (1,3).....this oscillation continues infinitely.....
Hope that helps some.....!!!!
