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# Pre-Calculus

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Hello! I posted a question earlier asking about a Pre-Calculus problem, but I'm afraid there was a small typo. I forgot to add what the equation was equal to. Thanks to CPHill for your answer to my previous question, however. This is the correct one.

m=2(nx+bn+bx)

If anyone can help me, it would be GREATLY appreciated! Thank you!

Guest Dec 6, 2017
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#1
+79819
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m=2(nx+bn+bx)

I think you wanted to solve for x

Divide both sides by 2

(m /2)  =  nx + bn + bx     subtract  bn from both sides

(m / 2) - bn  =   nx + bx     simplify the left side as a single fraction

[ m - 2bn ] / 2     =  nx + bx      factor the right

[ m - 2bn ] / 2   =   x [ n + b]        divide both sides by  [ n + b ]

[ m - 2bn]  / [ 2 ( n + b) ]  =  x

CPhill  Dec 6, 2017
#2
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Awesome! Thank you so much! It means a lot to me!

Have a wonderful evening. Thank you for all you do!

Guest Dec 6, 2017
#3
+79819
+1

Thanks....we always appreciate those compliments....!!!

CPhill  Dec 6, 2017

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