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What would be the answer please?

The mean number of accidents in a shoe factory is 0.10 per day. What is the probability that during a randomly selected day, there will be:

a) no accidents

b) exactly 1 accident

c) at least 1 accident

milnez  Sep 17, 2016

Best Answer 

 #1
avatar+26329 
+10

The Poisson distribution gives the probability of k events in an interval as \(p = \frac{\lambda^ke^{-\lambda}}{k!}\) where \(\lambda\)  is the mean.

 

So:

 

1. \(p(k=0)=e^{-0.1} \rightarrow 0.905\) 

 

2. \(p(k=1)=0.1e^{-0.1} \rightarrow 0.0905\) 

 

3. Ther probability of at least one accident is 1 - (the probability of exactly no accidents plus the probability of exactly one accident).

Alan  Sep 17, 2016
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1+0 Answers

 #1
avatar+26329 
+10
Best Answer

The Poisson distribution gives the probability of k events in an interval as \(p = \frac{\lambda^ke^{-\lambda}}{k!}\) where \(\lambda\)  is the mean.

 

So:

 

1. \(p(k=0)=e^{-0.1} \rightarrow 0.905\) 

 

2. \(p(k=1)=0.1e^{-0.1} \rightarrow 0.0905\) 

 

3. Ther probability of at least one accident is 1 - (the probability of exactly no accidents plus the probability of exactly one accident).

Alan  Sep 17, 2016

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