The line y= 3x-p+1 is a tangent to the parabola y= x2
Evaluate p
Thank you
The slope at any point on the parabola = 2x
The slope of the line is 3
So.....equating slopes, we have that 2x = 3 ⇒ x = 3/2
So....at x = 3/2, x^2 = 9/4 = y
So.......to find p we have
9/4 = 3(3/2) - p + 1
9/4 = 9/2 + 1 - p
9/4 = 22/4 - p
p = 13/ 4
Here's the graph : https://www.desmos.com/calculator/kzzakejx7h