if the sides of a parallelogram and an included angle are 6,10 and 100degrees repsepctively,find the legth of the shorter diagonal?
+33616 You can use the cosine rule here. First though, you must find the angle that is less than 90°. This will be 180°-100° = 80°.
If the length of the shorter diagonal is "a" then, a, 6 and 10 are the lengths of the sides of a triangle in which the angle opposite side "a" is 80°.
Use a2 = 62 + 102 -2*6*10*cos(80°)
I'll leave you to find "a" from this.
.
+33616 You can use the cosine rule here. First though, you must find the angle that is less than 90°. This will be 180°-100° = 80°.
If the length of the shorter diagonal is "a" then, a, 6 and 10 are the lengths of the sides of a triangle in which the angle opposite side "a" is 80°.
Use a2 = 62 + 102 -2*6*10*cos(80°)
I'll leave you to find "a" from this.
.
