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Suppose that the height of a plane t minutes after take off is h(t)=3500ln(t+1) feet for 0 <= t <= 15.

 

How fast is the plane rising 5 minutes after take off?

 Feb 29, 2016
edited by gretzu  Feb 29, 2016

Best Answer 

 #1
avatar+270 
+5

so I got

 

h(t) = 3500ln(t+1)

h'(t) = 3500 / t+1

h'(5) = 3500 / 5+1 = 3500/6 = 583.33 ft/sec

 

Anyone know if that sounds right? 

 Feb 29, 2016
 #1
avatar+270 
+5
Best Answer

so I got

 

h(t) = 3500ln(t+1)

h'(t) = 3500 / t+1

h'(5) = 3500 / 5+1 = 3500/6 = 583.33 ft/sec

 

Anyone know if that sounds right? 

gretzu Feb 29, 2016
 #2
avatar+128475 
+5

Correct, gretzu.....!!!

 

 

 

cool cool cool

 Feb 29, 2016
 #3
avatar+270 
0

Awesome, Thanks! laughlaughlaugh

gretzu  Mar 1, 2016

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