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# Question

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An algebra class has 9 students and 9 desks. For the sake of variety, students change the seating arrangement each day. How many days must pass before the class must repeat a seating arrangement? Correct days must pass before a seating arrangement is repeated. Suppose the desks are arranged in rows of 3. How many seating arrangements are there that put Larry, Moe, & Curly in the front seats? There are Incorrect seating arrangements that put them in the front seats.

Guest Feb 18, 2017

#6
+836
+6

Curly is soitenly my favorite.

Here's a clip of the funniest of all.

(Curly isn't in this one, though.)

GingerAle  Feb 18, 2017
edited by GingerAle  Feb 18, 2017
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#1
+10672
+5

nPr = 9 P 9 =  362880 different seating arrangements   ( 9! = 362880)

with  Larry Moe Curly in fron row.....    9 C 3 =84  ways   ( 9! /(6 x 6!) )

(I think !)

ElectricPavlov  Feb 18, 2017
#2
+79903
+5

I agree with EP's first answer........

I see the second situation a little differently

We can arrange Larry, Curly and Moe  in 3!  ways in the front row and the other students in 6! ways in the other desks....so

3! * 6!  =  4320 arrangements

CPhill  Feb 18, 2017
#3
+10672
+5

....and I agree with Chris'  second answer    !!!

ElectricPavlov  Feb 18, 2017
#4
+836
+5

Well, I would like to be sitting right behind them! nyuk nyuk nyuk

I love the three stooges!

GingerAle  Feb 18, 2017
#5
+79903
+5

CPhill  Feb 18, 2017
#6
+836
+6

Curly is soitenly my favorite.

Here's a clip of the funniest of all.

(Curly isn't in this one, though.)

GingerAle  Feb 18, 2017
edited by GingerAle  Feb 18, 2017
#7
+91262
+5

THAT WAS HILARIOUS!!

Thanks for sharing Ginger :))

Melody  Feb 18, 2017

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