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# rational functions

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The average cost per unit C(x), in dollars, to produce x units of toy cars is given by C(x)=(8000)/(x−50)C(x)=(8000)/(x−50). What is the approximate cost per unit when 1250 toy cars are produced?

Guest Aug 20, 2017
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Intepretation: Approx for $$x$$ in the function $$C(x)=\frac{8000}{x-50}$$ when $$C(x)=1250$$

Solution:

Solve for $$x$$ when $$\frac{8000}{x-50}=1250$$

Multiple both sides by a factor of $$x-50$$:

$$1250(x-50)=8000$$

Expand:

$$1250x-62500=8000$$

Move the numerical term to the right:

$$1250x=70500$$

Divide both sides by the greatest common divisor of $$1250$$ and $$70500$$ (Which is equal to $$250$$)

$$5x=282$$

Divide both sides by $$5$$:

$$x =\frac{282}{5}$$

$$=56.4 \approx 56$$

Done :D

(You accidently posted the formula for $$C(x)$$ in your question two times, be careful.)

Jeffes02  Aug 20, 2017

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