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avatar+1904 

Rationalize the denominator to these expressions and show how you got your answer

 

I.)  \(\frac{5}{\sqrt{2}}\)

 

II.)  \(\frac{10}{\sqrt[3]{4}}\)

 

III.)  \(\frac{5+\sqrt{2}}{5-\sqrt{2}}\)

 

IV.) \(\frac{\sqrt{3}}{{tan}^{-1}(\sqrt{3})}\)

 

V.)  \(\frac{3}{\frac{\sqrt[5]{6}}{\sqrt[7]{6}}}\) 

 Jun 4, 2016
 #1
avatar+128570 
+5

I)     5/ √2   multiply top/bottom by √2  = 5√2 / [√2 * √2]  = [5√2] / 2  

 

II)  10/ ∛4   multiply top/bottom by  42/3  = 10 * 42/3 / 4  = [ 5 * 42/3 ] / 2  

 

III)  [ 5 + √2] / [ 5 - √2]     multiply top/bottom by [5 + √2]

 

     ([5 + √2] [ 5 + √2]) / [ 25 - 2]   =  [25 + 10√2 + 2] / 23  = [ 27 + 10√2] / 23

 

IV)  √3 / arctan (√3)  =   √3 / [pi/ 3] =   [3 √3] / pi

 

V)   3 / [ 61/5 / 61/7 ]   = [3 * 6 1/7 ] / 61/5      multilply top/bottom by 64/5 =

 

     [ 3 * 61/7 * 64/5] / [61/5 * 64/5]  = [ 3 * 633/35]  / [ 6]  =     633/35 / 2

 

 

cool cool cool

 Jun 4, 2016

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