Hello and thank you, yesterday was the first time I've used web2.0calc (your site came up when I was using google calculator), I would like to expand on the problem and thank you for the answers so far, maths is not my strong point and I'm really very grateful.

I’ve reworked a formula that patinas certain metals and to date, I've formulated as the answer(s) below. (answered by melody)

However, I'm basing this on a total solution of 1750ml, now what I'm trying to do is trying to calculate how much I will need for coverage:

so, I know that if I prepare the kit as follows A=1000ml B= 500ml C=250ml (based on a basic recipe I’ve found on-line), I can use the formula below to easy create a 300ml solution, however, the solutions need to be prepared fresh each time.

A | B | C | TOTAL | WORKING |

1000 | 500 | 250 | 1750 | 1750/300 = 5.8333 |

1000/5.83 | 500/5.83 | 250/5.83 | 1750/5.83 | |

171ml | 86ml | 43ml | 300ml | answered by melody |

So I need to calculate how much I need for a given volume, so that SAxH for example 2000mm x 4000mm x 0.5mm gives me a volume required: SA =8000mm Volume 4000ml, the chemicals are expensive and work best if they just sit on the surface not submerged, so my tests show that height is 0.5mm (on a flat surface with surface tension) this is fixed, my question is with the existing formula how would i calculate the amount required for variable amounts such as I needed 4000ml or 2000ml for example, it would give me the amounts of A, B and C respectively.

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A | B | C |

1000 ml Water | 500 ml Water | 250 ml Water |

17g Chemical X | 22g Chemical Y | 11g Chemical Z |

SA = (W=2000 mm *variable* x L=4000 mm *variable*) =8000 mm sq x H (0.5mm *fixed*) = Volume 4000 ml

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Hope this makes sense :-)

Many Thanks

Nigel

Guest May 28, 2017