Find the equation of the line parallel to 7y+2x−10=0 that passes through the point (2, 2).
+245 *Parallel lines have the same slope*
Begin by making y a function of x
7y + 2x -10 = 0
7y + 2x= 10
7y=10 -2x
y= (10/7) - 2/7 x
knowing that the equation of a line is y = mx + b where m is the slope and b is the y intercept you can rewrite the equation in this format.
y = - (2/7) x + (10/7)
The slope is -2/7
Using point-slope form we can make a line parallel to the equation:
y-y1 = m (x - x1)
y - 2 = -2/7 ( x- 2)
As you can see these two lines are now parallel.
