simplify 1-cos(^2x)/sec(^2-1)

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simplify 1-cos(^2x)/sec(^2-1)

Guest Mar 31, 2015

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Best Answer

+128475

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I assume this is :

[1-cos(^2x)]/ [sec^2x-1] =

sin^2x / tan^2x =

sin^2x / [sin^2x/cos^2x] =

cos^2x

CPhill Mar 31, 2015

1⁺⁰ Answers

+128475

+5

Best Answer

I assume this is :

[1-cos(^2x)]/ [sec^2x-1] =

sin^2x / tan^2x =

sin^2x / [sin^2x/cos^2x] =

cos^2x

CPhill Mar 31, 2015

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