Simplify: the square root of 3 (-16xy^6)

$$\sqrt3(-16xy^6)\\\\
=-16\sqrt3xy^6\\\\\\
$or do you mean$\\\\
\sqrt{3(-16xy^6)}\\\\
=\sqrt{-3*16xy^6}\\\\
=4y^3\sqrt{-3x}\\\\
=4y^3\sqrt{3x}\;i\\\\
\;$i is the imaginary number $\sqrt{-1}$$

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