what is the x-intercept of a line with a slope of -4/5 and passes though (-1, 8)?
What is the x-intercept of a line with a slope of -4/5 and passes though (-1, 8)
Use the point-slope form
y - 8 = (-4/5)(x - [ -1 ])
y - 8 = (-4/5) (x + 1)
y = (-4/5)x - 4/5 + 8
y =(-4/5)x - 4/5 + 40/5
y = (-4/5)x + 36/5
This iis in slope intercept form .......the y intercept is at 36/5 ...... [i.e., the point (0, 36/5) ]
Sorry CPhill, your answer was right if the guest is to find the y-intercept but he was actually requesting us to find the x-intercept.
y = (-4/5)x + 36/5 Copying CPhill's last step. That's is the equation for slope-intercept form.
Set y to 0
0 = -4x / 5 + 36 / 5
Multiply by 5,
-4x + 36 = 0
-4x = -36
x = 9
The x-intercept is 9. Which is at the point (9 , 0)