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what is the x-intercept of a line with a slope of -4/5 and passes though (-1, 8)?

 Jul 26, 2016
 #1
avatar+128732 
+5

What is the x-intercept of a line with a slope of -4/5 and passes though (-1, 8)

 

Use the point-slope form

 

y - 8 = (-4/5)(x - [ -1 ])

 

y - 8 = (-4/5) (x + 1)

 

y = (-4/5)x - 4/5 + 8

 

y =(-4/5)x - 4/5 + 40/5

 

y = (-4/5)x + 36/5

 

This iis in slope intercept form  .......the y intercept is at   36/5 ......  [i.e.,  the point (0, 36/5)  ]

 

 

 

cool  cool cool

 Jul 26, 2016
 #2
avatar+9664 
0

Sorry CPhill, your answer was right if the guest is to find the y-intercept but he was actually requesting us to find the x-intercept.

 

y = (-4/5)x + 36/5 Copying CPhill's last step. That's is the equation for slope-intercept form.

Set y to 0

0 = -4x / 5 + 36 / 5

Multiply by 5,

-4x + 36 = 0

-4x = -36

x = 9

 

The x-intercept is 9.  Which is at the point (9 , 0)

 Jul 27, 2016
edited by MaxWong  Jul 27, 2016

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