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$$\mathrm{\ }$$If there is seven thousand earthquakes in christchurch and 7/10ths are below a magnitude 6 then how many are above a magnitude 6 

Guest Mar 1, 2015

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 #2
avatar+91432 
+5

Great answer anon,

another way to do it is

 

$${\frac{{\mathtt{3}}}{{\mathtt{10}}}}{\mathtt{\,\times\,}}{\mathtt{7\,000}} = {\mathtt{2\,100}}$$

 

Can you see why ?

If anyone wants me to explain then please ask :)

Melody  Mar 1, 2015
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2+0 Answers

 #1
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+5

The answer is 2100

$${\frac{{\mathtt{7}}}{{\mathtt{10}}}}{\mathtt{\,\times\,}}{\mathtt{7\,000}} = {\mathtt{4\,900}}$$, 1) This is the first step: to find 7/10ths of 7000

 

$${\mathtt{7\,000}}{\mathtt{\,-\,}}{\mathtt{4\,900}} = {\mathtt{2\,100}}$$    , 2) Then Subract

Guest Mar 1, 2015
 #2
avatar+91432 
+5
Best Answer

Great answer anon,

another way to do it is

 

$${\frac{{\mathtt{3}}}{{\mathtt{10}}}}{\mathtt{\,\times\,}}{\mathtt{7\,000}} = {\mathtt{2\,100}}$$

 

Can you see why ?

If anyone wants me to explain then please ask :)

Melody  Mar 1, 2015

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