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solve 4cos^2ϴ=0, 0degrees ≤ 0 ≤ 360 degrees

 Jan 18, 2017
 #1
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4cos^2ϴ = 0  divide both sides by 4

 

cos^2ϴ = 0    take the sq rt of both sides

 

cosϴ = 0     at   90°  and 270°

 

 

 

cool cool cool

 Jan 18, 2017

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