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solve the equation $$x^2+x-10=0$$

 Jan 24, 2015

Best Answer 

 #1
avatar+128731 
+5

 

 

 

x^2 + x - 10 = 0   this won't factor....using the onsite solver, we have

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{10}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\frac{\left({\sqrt{{\mathtt{41}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}{{\mathtt{2}}}}\\
{\mathtt{x}} = {\frac{\left({\sqrt{{\mathtt{41}}}}{\mathtt{\,-\,}}{\mathtt{1}}\right)}{{\mathtt{2}}}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{3.701\: \!562\: \!118\: \!716\: \!424\: \!3}}\\
{\mathtt{x}} = {\mathtt{2.701\: \!562\: \!118\: \!716\: \!424\: \!3}}\\
\end{array} \right\}$$

 

 Jan 24, 2015
 #1
avatar+128731 
+5
Best Answer

 

 

 

x^2 + x - 10 = 0   this won't factor....using the onsite solver, we have

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{10}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\frac{\left({\sqrt{{\mathtt{41}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}{{\mathtt{2}}}}\\
{\mathtt{x}} = {\frac{\left({\sqrt{{\mathtt{41}}}}{\mathtt{\,-\,}}{\mathtt{1}}\right)}{{\mathtt{2}}}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{3.701\: \!562\: \!118\: \!716\: \!424\: \!3}}\\
{\mathtt{x}} = {\mathtt{2.701\: \!562\: \!118\: \!716\: \!424\: \!3}}\\
\end{array} \right\}$$

 

CPhill Jan 24, 2015

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