Solve the exponential equation 2^(2x+2)+7=71

2^(2x+2)+7=71

2^(2x+2)+7-7=71-7

2^(2x+2)=64

2^2x * 2^2=64

2^2x * 2^2/2^2=64/2^2

2^2x=16

4^x=16

square root of 16 = 4

X=4

I'm 13 and in grade eight :)

Not quite, HelpMeWithThisPlease.....but....good try.....

Going from

2^(2x+2)=64  equate  bases

2^(2x + 2)  = 2^6   solve for the exponents

2x+ 2  = 6      divide through by 2

x + 1  = 3   →   x  = 2