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cos x(2cosx^2+1)=0

Guest Mar 20, 2017
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I assume this is cos x*(2[cos x]^2 + 1) = 0

 

The term in brackets can never be zero, so we must have cos x = 0

 

That is x = pi/2, 3pi/2 in the range between 0 and 2pi.

 

.

Alan  Mar 20, 2017

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