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Solve: 10xsquared - 27x + 5 = 0

 Jan 3, 2017

Best Answer 

 #2
avatar
+5

Solve for x:
10 x^2 - 27 x + 5 = 0

The left hand side factors into a product with two terms:
(2 x - 5) (5 x - 1) = 0

Split into two equations:
2 x - 5 = 0 or 5 x - 1 = 0

Add 5 to both sides:
2 x = 5 or 5 x - 1 = 0

Divide both sides by 2:
x = 5/2 or 5 x - 1 = 0

Add 1 to both sides:
x = 5/2 or 5 x = 1

Divide both sides by 5:
Answer: |x = 5/2             or                x = 1/5

 Jan 3, 2017
 #1
avatar+83 
+5

 

(2x−5) (5x−1)

 Jan 3, 2017
 #2
avatar
+5
Best Answer

Solve for x:
10 x^2 - 27 x + 5 = 0

The left hand side factors into a product with two terms:
(2 x - 5) (5 x - 1) = 0

Split into two equations:
2 x - 5 = 0 or 5 x - 1 = 0

Add 5 to both sides:
2 x = 5 or 5 x - 1 = 0

Divide both sides by 2:
x = 5/2 or 5 x - 1 = 0

Add 1 to both sides:
x = 5/2 or 5 x = 1

Divide both sides by 5:
Answer: |x = 5/2             or                x = 1/5

Guest Jan 3, 2017
 #3
avatar+118608 
0

 10xsquared - 27x + 5 = 0

 

you can use the quadratic formula

 

https://www.youtube.com/watch?v=O8ezDEk3qCg

 

OR

 

\( 10x^2 - 27x + 5 = 0\)

 

10*5=50

look for 2 mumbers that multiply to 50 and add to -27

that is easy -25 and -2

 

so change -27x to -25x-2x

 

 

\(​​​​10x^2-25x-2x+5=0\\ ​​​​5x(2x-5)-1(2x-5)=0\\ ​​​​(5x-1)(2x-5)=0\\ 5x-1=0 \quad or \quad 2x-5=0\\ 5x=1 \qquad or \qquad 2x=5\\ x=0.2 \qquad or \qquad x=2.5\\\)

 Jan 3, 2017

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