+140 i need to solve
sqrt(3x-5)=x-2 i got these steps
3x-5=(x-2)(x-2)
3x-5=x^2-4x+4
0=x^2-x+9
a=1 b=-1 c=9
then simplified to
x=(1+sqrt(-35))/2
and i am stuck here on how to simplify further
+128475 Let's go from this step :
3x-5=x^2-4x+4 subtract 3x from both sides and add 5 to both sides
0 = x^2 -7x + 9 this will not factor........using the quadratic formula, the two solutions are :
[ 7 + √13] / 2 = about 5.3028 or
[ 7 - √13] / 2 = about 1.6792
The second solution is extraneous, since it makes the right side of the original equation negative......and we can't ever get a negative answer from a positive root......this solution results from the squaring of both sides [which often happens in these types of problems].....so.....
Only the first solution is "good"
