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subract the sum of m^2n - 2mn^2 and 2m^2n - m - n^3 + 2mn^2 from m^3 - n^3

 Aug 14, 2015

Best Answer 

 #1
avatar+118608 
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$$\\(m^3 - n^3)-( m^2n - 2mn^2 )-( 2m^2n - m - n^3 + 2mn^2) \\\\
=m^3 - n^3 -m^2n + 2mn^2 -2m^2n + m + n^3 - 2mn^2 \\\\
=m^3 -m^2n -2m^2n+ 2mn^2 - 2mn^2 + m \\\\
=m^3 -3m^2n + m \\\\$$

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 Aug 15, 2015
 #1
avatar+118608 
+5
Best Answer

$$\\(m^3 - n^3)-( m^2n - 2mn^2 )-( 2m^2n - m - n^3 + 2mn^2) \\\\
=m^3 - n^3 -m^2n + 2mn^2 -2m^2n + m + n^3 - 2mn^2 \\\\
=m^3 -m^2n -2m^2n+ 2mn^2 - 2mn^2 + m \\\\
=m^3 -3m^2n + m \\\\$$

Melody Aug 15, 2015

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