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tan^2(x)+tan(x)

 Jul 4, 2015

Best Answer 

 #2
avatar+118608 
+10

Thanks CPhill,

 

CPhill and I   have both interpreted your question to mean

$$y=tan^2x+tanx$$

 

If x=0 then y=0 because   tan0=0

 

If y=0 then

$$\\tanx(tanx+1)=0\\\\
tanx=0\;\;or\;\;tanx+1=0\\\\
sinx=0\;\;or\;\;tanx=-1\\\\
x=n\pi\pm \frac{\pi}{2}\;\;\;or\;\;\;x=n\pi\pm \frac{3\pi}{4}\qquad n\in Z$$

 

 

My answer is the same as CPhill"s

 Jul 5, 2015
 #1
avatar+128578 
+10

Here's a graph.........https://www.desmos.com/calculator/wpfchryj3k

 

This function  intersects the x axis   at    -45° + k*180°  and at   0° + k*180°  {where k is an integer}

 

It only intersects the y axis at the origin....!!!!

 

 

 Jul 4, 2015
 #2
avatar+118608 
+10
Best Answer

Thanks CPhill,

 

CPhill and I   have both interpreted your question to mean

$$y=tan^2x+tanx$$

 

If x=0 then y=0 because   tan0=0

 

If y=0 then

$$\\tanx(tanx+1)=0\\\\
tanx=0\;\;or\;\;tanx+1=0\\\\
sinx=0\;\;or\;\;tanx=-1\\\\
x=n\pi\pm \frac{\pi}{2}\;\;\;or\;\;\;x=n\pi\pm \frac{3\pi}{4}\qquad n\in Z$$

 

 

My answer is the same as CPhill"s

Melody Jul 5, 2015

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