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The area of a sector of a circle with central angel pi/16 is 64pi inch^2. Find the exact radius of the circle.

 Jul 25, 2014

Best Answer 

 #1
avatar+118613 
+5

$$\\Area\;\; of\;\; circle =\;\;\pi r^2\\
\mbox{Now let's look at the area of this sector}\\\\
\begin{array}{rlll}
64\pi&=&\dfrac{\frac{\pi}{16}}{2\pi}\pi r^2\\\\
64\pi&=&\frac{\pi}{16}\times \frac{1}{2\pi}\times \pi r^2\\\\
64&=&\frac{1}{16}\times \frac{1}{2}\times r^2\\\\
64&=&\frac{1}{32}\times r^2\\\\
64\times 32&=&r^2\\\\
r^2&=&64\times 32\\\\
r^2&=&64\times 16\times 2\\\\
r&=&8\times 4\times \sqrt2\\\\
r&=&32\sqrt2\;inches\\\\
\end{array}$$

.
 Jul 25, 2014
 #1
avatar+118613 
+5
Best Answer

$$\\Area\;\; of\;\; circle =\;\;\pi r^2\\
\mbox{Now let's look at the area of this sector}\\\\
\begin{array}{rlll}
64\pi&=&\dfrac{\frac{\pi}{16}}{2\pi}\pi r^2\\\\
64\pi&=&\frac{\pi}{16}\times \frac{1}{2\pi}\times \pi r^2\\\\
64&=&\frac{1}{16}\times \frac{1}{2}\times r^2\\\\
64&=&\frac{1}{32}\times r^2\\\\
64\times 32&=&r^2\\\\
r^2&=&64\times 32\\\\
r^2&=&64\times 16\times 2\\\\
r&=&8\times 4\times \sqrt2\\\\
r&=&32\sqrt2\;inches\\\\
\end{array}$$

Melody Jul 25, 2014
 #2
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Thank you

 Jul 25, 2014

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